[tex]\begin{gathered} 2x-10y=4\ldots(1) \\ x-y=6 \\ x=y+6\ldots(2) \\ \text{Substitute the value of x in the equation (1).} \\ 2(y+6)-10y=4 \\ 2y+12-10y=4 \\ -8y=4-12 \\ y=\frac{-8}{-8} \\ y=1 \\ \text{Now, substitute the value of y in the equaton (2)} \\ x=1+6 \\ x=7 \\ \text{The ordered pair is (7,1).} \end{gathered}[/tex]
