contestada

Light incident at 650 in air strikes a transparent material and produces reflected light that is linearly polarized in just one direction, satisfying the condition of Brewster’s angle. a) Determine the index of refraction of the material. b) Calculate the angle of incidence that would yield completely polarized reflected light if the transparent material were water.Index of refraction for water = 1.33.

Respuesta :

a)

[tex]\begin{gathered} n1sin(\theta i)=n2sin(\theta r) \\ n2=\frac{n1sin(\theta i)}{sin(\theta r)} \\ where: \\ \theta r=180-90-65=25 \\ so: \\ n2=\frac{sin(65)}{sin(25)} \\ n2=2.14 \end{gathered}[/tex]

b)

[tex]\begin{gathered} \theta_B=tan^{-1}(\frac{n2}{n1}) \\ \theta_B=tan^{-1}(\frac{1.33}{1}) \\ \theta_B\approx53.06^{\circ} \end{gathered}[/tex]

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