Let the width be x cm.
Since the length is twice the width, therefore, its length is 2x cm.
The area of the rectangle is
[tex]2x^2cm^2[/tex]Accordingly,
[tex]\begin{gathered} 2x^2=50 \\ x^2=25 \\ x=\pm5 \end{gathered}[/tex]Since width of the rectangle can't be negative,
therefore, its width is 5 cm and length is 10 cm.
