Solution:
Given:
[tex]\begin{gathered} Total\text{ dismissed}=8 \\ \\ \\ Over\text{ 50}=6 \\ Under\text{ 50}=18 \\ Total\text{ employees}=24 \end{gathered}[/tex]
If the dismissed employees were selected at random what is the probability that exactly 6 employees were over 50 will be;
[tex]\begin{gathered} \frac{^6C_6\times^{18}C_2}{^{24}C_8}=\frac{1\times153}{735471} \\ =\frac{153}{735471} \\ =\frac{1}{4807} \end{gathered}[/tex]
Therefore, the probability that exactly 6 employees were over 50 will be;
[tex]\frac{1}{4807}[/tex]