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An airplane is headed for the airport,14 miles away. If the airplane is at  an altitude of 5000 feet, what is the angle of depression, to the nearest tenth of a degree, from the airplane to the airport? (1 mile = 5280 feet)

Respuesta :

Answer:

3.9 degrees

Explanation

Given the following

Altitude of the plane = 5000ft = opposite

distanace of the plane from the airport = 14miles = 73,920feet

Required

angle of depression

Using the trigonometry identity

Sin theta = opposite/hypotenuse

Sin theta = 5000/73920

sin theta = 0.06764

theta = arcsin(0.06764)

theta = 3.9 degrees

Hence the angle of depression to the nearest tenth is 3.9 degrees

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