A line is drawn so it passes through the points (11,-4) and (-5.9). What is the slope ofthe line? State your answer as a decimal rounded to the tenths place. If your answeris a whole number, include a zero in the tenths place. Example: 37 should be writtenas 37.0.

Respuesta :

The slope of a line, also known as the gradient of a line is the ratio of the change in the vertical values to the horizontal values of the given points.

The points given are

[tex](11,-4)\text{ and (-5,9)}[/tex]

The horizontal values are

[tex]x_1=11,x_2=-5[/tex]

The vertical values are

[tex]y_1=-4,y_2=9[/tex]

We can now apply the formula to compute the slope

[tex]\text{slope}=\frac{y_2-y_1}{x_2-x_1}[/tex]

Hence

[tex]\text{slope}=\frac{9-(-4)}{-5-11}[/tex]

Thus

[tex]\text{slope}=\frac{13}{-16}=-0.8125[/tex]

Thus, the slope rounded to the nearest tenths place will be

[tex]-0.8[/tex]

The slope is -0.8