a certain spring stretches 8.4 cm when it supports a mass of 0.89 kg . if the elastic limit is not reached, how far will it stretch when it supports a mass of 10 kg ?

Respuesta :

The correct answer is 1 cm. the spring will stretch when it supports a mass of 10 Kg.

What is Hooke’s Law?

According to Robert Hooke, an English scientist, for relatively minor deformations of an item, the displacement or amount of the deformation is directly proportional to the deforming force or load.

Hooke aimed to show how a spring's elasticity and the forces acting on it are related. According to Hooke's Law, a spring's extension is proportional to the load placed on it. As long as the load does not exceed the material's elastic limit, a variety of materials will adhere to this rule.

From Given data,

For each Kilogram, spring stretched 0.89 / 8.4 = 0.1 cm

Then from Hooke’s law we can conclude

0.1cm x 10 Kg = 1 cm. the spring will stretch

To learn more about Hooke’s law for string stretch from the given link

https://brainly.com/question/14477435

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