Respuesta :
Minimum resolvable wavelength separation will be 8.333x10⁻¹² m.
Number of lines per mm is N ' = 1200
Width of the grating W = 5 cm = 50 mm
Therefore number of lines in the grating N = WN '
= 50 x1200
= 60000
Order n = 1
wavelength \lambda = 500 nm
We know resolving power nN = \lambda/\Delta \lambda
From this \Delta \lambda = \lambda / nN
= (500 nm) / ( 1 x 60000)
= 8.333x10 -3 nm
= 8.333x10 -3 x10 -9 m
= 8.333x10⁻¹² m
The wavelength of a wave describes how lengthy the wave is. The distance from the "crest" (top) of 1 wave to the crest of the following wave is the wavelength. Alternately, we can degree from the "trough" (bottom) of 1 wave to the trough of the subsequent wave and get the equal price for the wavelength.
Wavelength: the space between one peak and the following in a chain of waves, or the distance between one trough and the following. It is also one of the “yardsticks” used to measure radiation.
The SI unit of wavelength is metre . At the same time as measuring wavelength the multiples or fractions of a metre is also used. Extensively, exponential powers of 10 are used whilst wavelengths are of a huge assets.
Learn more about Wavelength here:-https://brainly.com/question/24452579
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