a spot of paint on a bicycle tire moves in a circular path of radius 0.310 m. when the spot has traveled a linear distance of 1.41 m, through what angle has the tire rotated? give your answer in radians, do not enter unit.

Respuesta :

Answer:  

Explanation:

Distance covered by painted spot in 1 rotation i.e pi radian = 2*pi*r

                                                  =  2*3.14*0.31

                                                  = 2pi*0.31 meters

This means,

                      In 2pi*0.31 meters the painted spot covers pi rad

                       2pi*0.31 m = 2pi rad

             so,     1 m = pi/(2*2pi*0.31) rad

            therefore in 1.41 m the painted spot covers

                 2pi*/(2*pi*0.31)= 4.54 rad

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