The molar mass of given acid H₂X is 85.1g/mol
Mass of the H₂X = 0.1873 grams
Molarity of NaOH = 0.1052 M
Thus, the balanced equation
H₂X (aq) +2 NaOH (aq) → Na₂X (aq) + 2H₂O(l)
Calculating moles of NaOH
For 1 mol H₂X we need 2 moles NaOH to produce 1 mole of Na₂X and 2 moles of H₂O
For 0.0022 moles of H₂X we need 0.0044 moles of NaOH
Volume of the NaOH = moles of NaOH / molarity of NaOH
Volume of the NaOH = 0.0044 moles / 0.1052 M
Volume of the NaOH = 0.04189 L = 41.89 mL
We just need 41.8 mL of NaOH
Since number of moles of H₂X is 0.0022
Number of moles= Mass/ Molar mass
0.0022= 0.1873/ Molar mass
Molar mass= 0.1873 / 0.0022
= 85.1 g/mol
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