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according to the u.s. census bureau, 19.1% of u.s. households are in the norheast. in addition 4.4% of u.s households earn $75,000/year or more and are located in the northeast. determine the probability that a randomly selected u.s. household earns more than $75,000/year, given that the household is located in the northeast.

Respuesta :

Given that the household is located in the northeast, there is a 0.230 probability that the randomly chosen US household makes more than $75,000.

Given info;

19.1% of US households, according to the US Census Bureau, are in the Northeast. Additionally, 4.4% of households in the US earn $75,000 or more annually and are situated in the northeast.

let, A represents the U.S. households in the Northeast.

     B represents the U.S. households earning $75,000 or more.

To determine the probability that a randomly selected US household earns more than $75,000/year, given that the household is located in the northeast.

P(A) = 19.1% = 0.191

P(A ∩ B) = 4.4% = 0.044

P(B I A) = P(A ∩ B) / P(A)

            = 0.044 / 0.191

            = 0.230

Hence, the probability that a randomly selected US household earns more than $75,000/year, given that the household is located in the northeast is 0.230.

To learn more about probability click here:

brainly.com/question/11234923

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