The probability that the total of the number on the dice exceeds 6 is 1/12.
When the two fair dice are thrown the total possible outcome are,
= 6 x 6
= 36
So, there are a total of 36 possible outcomes.
If one of the dice shows 3, then the total favorable outcomes that the sum of the numbers on the dice exceeds 6 is,
(3+4)(3+5)(3+6)
Hence, the total possible favorable outcomes are 3.
Probability of an event = Total favorable outcomes/total possible outcomes.
Probability that the sum exceeds 6 = 3/36
Probability that the sum exceeds 6 = 1/12
So, Probability that the sum exceeds 6 is 1/12.
To know more about probability, visit,
https://brainly.com/question/13604758
#SPJ4
