how much heat does it take to increase the temperature of 1.80 mol of an ideal gas by 50.0 k near room temperature if the gas is held at constant volume and is (a) diatomic; (b) monatomic?

Respuesta :

The heat provided to the diatomic gas and monoatomic gas is 1870.65 J and 1122.39 J respectively.

What is the specific heat capacity?

The specific heat of a substance can be defined as the quantity of heat required to raise the temperature of the substance with mass in one unit by one-degree Celcius.

Whenever the heat can be lost or absorbed the substance's temperature  will be changed:

Q = m.C.ΔT

Given, the number of moles of the gas, n = 1.8 mol

The change in the temperature, ΔT = 50 K

The molar specific heat at constant volume for the diatomic gas:

[tex]C_v =\frac{5}{2}R[/tex]

Heat provided to the diatomic gas:

[tex]Q = n\times C_v \times \triangle T[/tex]

Q = 1.8 × (5/2) R × 50

Q = 1.8 × (5/2) ×8.314 × 50

Q = 1870.65 J

The molar specific heat at constant volume for the monoatomic gas:

[tex]C_v =\frac{3}{2}R[/tex]

Heat provided to the monoatomic gas:

[tex]Q = n\times C_v \times \triangle T[/tex]

Q = 1.8 × (3/2) R × 50

Q = 1.8 × (3/2) ×8.314 × 50

Q = 1122.39 J

Learn more about specific heat capacity, here:

brainly.com/question/28302909

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