Respuesta :
The mass of water that contains same number of hydrogen atoms as 34 g of ammonia is 54 g.
First calculate the number of moles in a hydrogen gas. The molar mass of ammonia(NH₃) is 17 g/mol. Hence, the number of moles for ammonia(NH₃) is
moles=34 g×(1 mol/17 g)
=2 mol
The relation between moles and number of atoms is given as
1 mol=6.022×10²³ atoms
Since 1 mol NH₃ contains 3 mol of hydrogen. Hence, the number of hydrogen atoms in 2 mol NH₃ is
2 mol NH₃×(3 mol H/1 mol N)×(6.022×10²³ atoms/1 mol H)
=(2×3×6.022×10²³ atoms)
=3.6132×10²⁴ atoms
The molecular formula of water is H₂O. First, we need to find out the number of moles in the calculated atoms of hydrogen. One mol of water contains 2 moles of H. Hence, the number of moles of water is
3.6132×10²⁴ atoms×(1 mol H/6.022×10²³ atoms)×(1 mol H₂O/2 mol H)
=(3.6132×10²⁴ mol of H₂O/6.022×10²³×2)
=(3.6132×10²⁴ mol of H₂O/1.2044×10²⁴)
=3 mol of H₂O
The molar mass of of H₂O(water) is 18 g/mol. Hence, the mass of water is
3 mol H₂O×(18 g H₂O/1 mol H₂O)
=54 g H₂O.
Therefore, the mass of water which contains the same number of hydrogen atoms as 34 g of ammonia is 54 g of H₂O.
To know more about the number of atoms
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