The number of moles CO₂ gas that are generated if we collect 40.46-ml of the gas over water at 24.2 degrees C and 1.3-atm is
Ideal gas law equation:
PV = nRT
⇒ n = (PV) / (RT)
Given,
P = 1.3 atm
V = 40.46 mL
R = 0.08201 L atm mol⁻¹
T = 24.2 + 273 = 297.2 K
substituting the values we get,
n = (1.3 atm × 40.46 mL × 1L/1000mL) / (0.08201 L atm mol⁻¹ × 297.2 K)
⇒ n = 0.052598 / 24.37
⇒ n = 0.0022
Hence, there are 0.0022 moles of CO₂ gas.
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