There will be 26 amino acids in the alpha helix with 50 angstroms width
Width of 1 alpha helix turn - 5.4 angstroms
No. Of turns present in 50 angstroms width = 50 / 5.4
No. Of turns = 7.4 turns
There are 3.6 amino acids residue per turn thus for 7.4 turns there will = 7.4 x 3.6
No. Of amino acids = 26.64 or 26 amino acids
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