Respuesta :
The K eq Assuming T is298 K and R is 8.315 . 10-3 kJ/mol*K, the standard free energy for the reaction shown in the diagram is -3.5 kJ/mol. 4.10 is the value.
What is mass action ratio Q?
- Ratio of mass actions. When a reaction is complete (i.e., when t = ), this ratio—which is equal to the equilibrium constant—is the product of all the product concentrations divided by the product of all the reactant concentrations.
- According to the law of mass action, the equilibrium constant at a given constant temperature is equal to the product of the reactant concentrations divided by the product of the product of the product of the products increased to their respective stoichiometric coefficients.
- Assuming T = 298 K and R = 8.315 x 10-3 kJ/mol*K, the reaction's standard free energy is -3.5 kJ/mol.This number is 4.10
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