The amount of S8 that would be generated, if the yield was 98%, is 47.1 grams.
Mass is a physical body's total amount of matter.
This chemical process is
8H2S + 4O2 = S8 + 8H2O
Moles to ratios
8 mol H₂S: 4 mol O2: 1 mol S8
Calculate the moles of2 5.0 grams of H2S
Molar mass is equal to mass in grams.
H2S molar mass equals 2 x 1 g/mol plus 32.1 g/mol to equal 34.1 g/mol.
25.0 g divided by 34.1 g/mol gives 0.733 moles of H2S.
Moles from 60.0 g of oxygen
O2 molar mass equals 2 x 16 g/mol, or 32.0 g/mol.
60.0 g / 32.0 g = 1.875 moles of oxygen.
State-restricting substance
8 moles of H2S to 4 moles of O2 is equal to 2/1 in theory.
Actual ratio: 0.733 moles of H2S to 1.875 moles of oxygen.
The limiting agent is H2S. (it is consumed completely whilce some O2 remains unreacted).
Find out how many moles of S8 were created from 0.733 moles of H2S.
0.18325 mol S8 is equal to 1 mol S8 / 8 mol H2S x 0.733 mol H2S.
0.18325 mol S to mass conversion
Moles times molar mass equals mass.
in molar mass S8 equals 8 mol x 32.1 g/mol, or 256.8 g/mol.
mass = 256.8 g/mol x 0.18325 mol, or 47.1 grams.
As a result, the S8 weighs 47.1 g.
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