sarah invests $8200 in a new savings account which earns 5.8% annual interest, compounded semi-annually.
what will be the value of her investment after four years?

Respuesta :

Answer:

  • The value after 4 years is $10307.11

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Given

  • Invested amount P = $8200,
  • Interest rate r = 5.8% = 0.058,
  • Compound number n = 2,
  • Time t = 4 years.

Find the future amount

  • [tex]A = P(1+r/n)^{nt}[/tex]
  • [tex]A = 8200(1+0.058/2)^{2*4}=8200*1.029^8=10307.11[/tex]

Answer:

$10,307.11

Step-by-step explanation:

Compound Interest Formula

[tex]\large \text{$ \sf A=P\left(1+\frac{r}{n}\right)^{nt} $}[/tex]

where:

  • A = Final amount.
  • P = Principal amount.
  • r = Interest rate (in decimal form).
  • n = Number of times interest is applied per year.
  • t = Time (in years).

Given:

  • P = $8,200
  • r = 5.8% = 0.058
  • n = 2 (semi-annually)
  • t = 4 years

Substitute the given values into the formula and solve for A:

[tex]\implies \sf A=8200\left(1+\dfrac{0.058}{2}\right)^{2 \times 4}[/tex]

[tex]\implies \sf A=8200\left(1+0.029\right)^{8}[/tex]

[tex]\implies \sf A=8200\left(1.029\right)^{8}[/tex]

[tex]\implies \sf A=8200\left(1.25696445...\right)[/tex]

[tex]\implies \sf A=10307.10856...[/tex]

Therefore, the value of Sarah's investment after four years is $10,307.11 (nearest cent).