Data:
P (perimeter) = 500 feet
W (width) = 90 feet
L (length) = ?
Formula:
P = 2*(L + W) or P = L + L + W + W
Solving:
P = 2*(L + W)
500 = 2*(L + 90)
500 = 2L + 180
2L = 500 - 180
2L = 320
L = [tex] \frac{320}{2} [/tex]
[tex]\boxed{\boxed{L = 160}}
\end{array}}\qquad\quad\checkmark[/tex]
Answer:
the length is 160 feet
