The final temperature of the steam at 10MPa is equal to 390 °C.
Gay-Lussac's law can be described as if the volume (V) of the gas remains constant the pressure (P) is directly proportional to the absolute temperature (T) of the gas.
Gay Lussca's law in the form of mathematical expression as follows:
P/T = k
The pressure at constant volume is directly proportional to the temperature of gas.
P ∝ T (where V of gas is constant)
or, [tex]{\displaystyle \frac{T_2}{T_1} =\big (\frac{P_2}{P_1}\big)^\frac{\gamma-1}{\gamma}[/tex] for isentropic compression
Given, the initial temperature of the steam, T₁ = 300°C =300 + 273 =573 K
The initial pressure of the steam, P₁ = 6 MPa
The final temperature of the steam, P₂ = 10MPa
The final temperature of the steam can be determined as:
[tex]{\displaystyle \frac{T_2}{573} =\big (\frac{10}{6}\big)^\frac{1.4-1}{1.4}[/tex]
T₂ = 663 K
T₂ = 663 K - 273 K
T₂ = 390 °C
Learn more about Gay Lussac's law, here:
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