So the resultant values are wrench,nails, hammer
What is push and pop in a stack?
TOP is a pointer that is used to keep track of the top element in the stack.
When we initialize the stack, we set its value to -1 so that we can compare TOP == -1 to see if the stack is empty.
When we push an element, the value of TOP is increased and the new element is placed in the position indicated by TOP.
When an element is popped, we return the element pointed to by TOP and reduce its value.
We check if the stack is already full before pushing.
We check if the stack is already empty before popping.
First hammers, nails, wrench will go and pop will be done in reverse case so option b is the right answer
Hence to conclude push and pop are the one-by-one methods executed
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