Respuesta :
The equation of given line in slope-intercept form is 5x – 4y + 20 = 0 if the line makes intercepts –4 and 5 on the x- and y-axes respectively.
The diagram of the straight condition y = mx + c is a line with m as incline, m and c as the y-block. This type of the direct condition is known as the incline block structure, and the upsides of m and c are genuine numbers. The incline, m, addresses the steepness of a line. The incline of the line is additionally named as inclination, in some cases. The y-catch, b, of a line, addresses the y-direction of the place where the chart of the line converges the y-hub.
We have x-intercept as -4 and y-intercept as 5
Equation of the line in intercept form is:
(x/a) + (y/b) = 1
Substituting the values of a and b, we get the equation as:
=>(x/-4) + (y/5) = 1
=>(-5x + 4y)/20 = 1
-=>5x + 4y = 20
=>5x – 4y + 20 = 0
Hence, line equation is 5x – 4y + 20 = 0
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(Complete question) is:
What is the equation of the given line in slope-intercept form if x-intercept is -4 and y intercept is 5?
