For each of the following precipitation reactions, calculate how many grams of the first reactant are necessary to completely react with 17.3 g of the second reactant.
Part A
2KI(aq)+Pb(NO3)2(aq)→PbI2(s)+2KNO3(aq)
m = 17.3
g
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Correct
Part B
Na2CO3(aq)+CuCl2(aq)→CuCO3(s)+2NaCl(aq)
m = g
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Part C
K2SO4(aq)+Sr(NO3)2(aq)→SrSO4(s)+2KNO3(aq)
m = g