The solutions to this system of linear equation 3x−2y=14 is ( [tex]\frac{2y + 14}{3}[/tex] , [tex]\frac{3x}{2}[/tex]-7).
Add 2y to both sides.
3x=14+2y
The equation is in standard form.
3x=2y+14
Divide both sides by 3.
[tex]\frac{3x}{3}[/tex] = [tex]\frac{2y + 14}{3}[/tex]
Dividing by 3 undoes the multiplication by 3.
x = [tex]\frac{2y + 14}{3}[/tex]
Now,
3x−2y=14
Subtract 3x from both sides.
−2y=14−3x
Divide both sides by −2.
[tex]\frac{-2y}{-2}[/tex] = [tex]\frac{14 - 3x}{-2}[/tex]
Dividing by −2 undoes the multiplication by −2.
y = [tex]\frac{14 - 3x}{-2}[/tex]
Divide 14−3x by −2.
y = [tex]\frac{3x}{2}[/tex] - 7
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