(-2, 13) is the solution (q, r) to this system of linear equations. 12q + 3r = 15 - 4q - 4r = - 44.
Linear equation is defined as the equation in which the greatest power of the variable is always one. Linear equation is also known as one-degree equation. In linear equation the standard form is
Ax + B = 0
where,
A = coefficient
B = constant
x = variable
The given equations are
12q + 3r = 15 ….. (1)
- 4q - 4r = - 44 ……. (2)
Multiply equation (2) by 3, we get
- 12q - 12r = - 132 ….. (3)
Now by adding the equations (1) and (3), we get
3r - 12r = 15 - 132
- 9r = - 117
r = 117/9 = 13
By Substituting the value of r in equation (2), we get
- 4q - 4 (13) = - 44
- 4q - 52 = - 44
- 4q = - 44 + 52
- 4q = 8
q = - 2
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QUESTION: What is the solution (q, r) to this system of linear equations? 12q + 3r = 15 - 4q - 4r = - 44.