.Suppose that the skateboarder is oscillating between the horizontal positions of 1.5 m to 4.5 m. If the skateboarder has a mass of 60 kg, and we de ne U = 0 at y = 0, what is the maximum energy of the skateboarder-Earth system? Explain.

Respuesta :

When a skateboarder oscillates between horizontal positions of 1.5 m and 4.5 m, the skateboarder-Earth system's maximum energy is 3000J. if the skateboarder weighs 60 kilograms.

An essential measure of a permanent magnet's material's strength is its maximum energy product. It is commonly expressed in terms of either kJ/m and is frequently labelled (BH)max. Is called maximum energy.

When a skateboarder oscillates, The skateboard's mass (mg) bears down vertically. As indicated by the red arrows and labels, this can be divided into two halves in the radial and tangential directions (they are not additional forces to m g ). Is called oscillation.

At x = 4.5m, the skateboarder's height is 5m.

At 4.5 meter's, the skateboarder's speed is zero potential energy or total Energy of the skateboarder at 4.5m = mgh

= 60*10*5 = 3000J

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