The disk has mass 110 kg and radius 3.8 m is he value of the full angular momentum of the woman-disk machine is 9,759.7 kgm²/s.
The given parameters;
Mass of the woman, M = 50kg angular pace of the disk, w = 0.8rev/s
Mass of the disk, radius, r = 4.3m m = 110kg
The value of the full angular momentum of the woman-disk machine is calculated as follows;
I t =I disk omega+I woman
I t =(I disk +I woman )
[tex]I t =( 1/2 x m x r ^ 2 + M x r ^ 2I \\t = (1/2 x 110 x 4.3 ^ 2 + 50 x 4.3 ^ 2) *[/tex]
[tex]I t = (1941.45kg x m ^ 2) x 5.0%I t =9, 759.7kg x m ^ 2[/tex]/
Thus, the value of the full angular momentum of the woman- disk machine is 9,759.7 kgm²/s
[tex]t = 9.759 * 0.7ka m ^ 2.[/tex]
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