contestada

(a) find the critical numbers of (if any), (b) find the open interval(s) on which the function is increasing or decreasing, (c) apply the First Derivative Test to identify all relative extrema, and (d) use a graphing utility to confirm your results.

Respuesta :

varshamittal029

The critical numbers of the function  x³ - 6x² + 15 is 0 and 4

The given function is x³ - 6x² + 15

To find the critical value first we need to find the derivative, then set the derivative f'(x) to zero

The derivative of  x³ - 6x² + 15 is

3x³⁻¹ - 2(6)x²⁻¹  = 0

3x² - 12x = 0

3x(x - 4) = 0

3x = 0

x = 0

x - 4 = 0

x = 4

so, x = 0 or 4

Therefore, the critical numbers of the function  x³ - 6x² + 15 is 0 and 4

To learn more about the derivatives refer here

https://brainly.com/question/28376218

#SPJ4

Otras preguntas