The new length of the unstretched hanging-spring is 70 cm.
Hooke's law states that the spring's length change as a result of a compressive or tensile load is directly proportionate to the size of the force placed on the spring. Mathematically,
F = kx
Where;
K is the spring constant, while x represents the spring's length change.
As per the question-
L is the spring's uncompressed length: L = 0.5 m
Weight F1 linked to the spring: F1 = 100 N
First weight's effect on elongation x1: 60 - 50 = 10 = .01 m.
As per the Hooke's law;
F1 = Kx1
K = F1/X1
K = 100 / 0.1
K = 1000 N/m
Spring constant = 1000 N/m.
For the added 100-N block.
F = Kx2
x2 = F/K
x2 = 100 + 100 / 1000
x2 = 0.2m
x2 = 20 cm
L = 50 + 20 = 70 cm.
Thus, new length of the unstretched hanging-spring is 70 cm.
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