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projectile a is launched horizontally at a speed of 20 meters per second from the top of a cliff and strikes a level surface below. 3 seonds later projectile b launched horizontally from the same location at a speed of 30 meters per second. the time it takes projectile b to reach the level surface is

Respuesta :

The time taken for projectile b to reach the level surface is 3 seconds.

Calculations:

According to the question;

Initial velocity = 0 m/s

Acceleration due to gravity = 9.81 m/s²

Time-taken for projectile A = 3s

Initial velocity of projectile B = 0 m/s

The height will be:

= 0.5 × a × t²

= 0.5 × 9.81 × 3²

= 44.145m.

The time is taken to projectile b:

44.145 = 0.5 × 9.81 × t²

t² = 44.145 / (0.5 × 9.81)

t² = 44.145 / 4.905

t² = 9

t = ✓9

t = 3 seconds

A projectile is any object thrown into space upon which the simplest appearing force is gravity. The number one pressure performing on a projectile is gravity.

Learn more about projectile here; https://brainly.com/question/24216590

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