a 5.0-m-diameter merry-go-round is turning with a 4.5 s period. part a what is the speed of a child on the rim? express your answer using two significant figures.

Respuesta :

The speed of the merry-Go-round is 3.492 m/s

Given: Time period of Merry-go-round = 4.5 seconds

Diameter of the ring = 5.0m

this implies Radius=2.5m

Distance Travelled to complete 1 circle

=  2πr = 2*π*2.5 = 5π

Time Taken to complete 1 circle = 4.5 seconds

Speed = Distance Travelled/time taken

⇒ speed = 5 pi / 4.5

speed = [tex]\frac{5 * 22}{7 * 4.5}[/tex]

speed = 110 / 31.5

speed = 3.492 m/s

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