a machine part has the shape of a solid uniform sphere of mass 230 g and diameter 2.70 cm . it is spinning about a frictionless axle through its center, but at one point on its equator it is scraping against metal, resulting in a friction force of 0.0200 n at that point.

Respuesta :

A machine part has the shape of a solid uniform sphere of mass 230 g and diameter 2.7 cm. The angular acceleration is 16.10 rad / s².

Given that, mass of the sphere is 230 g

diameter is 2.7 cm

Frictional force = 0.02N

Now, we need to calculate angular acceleration. We know the formula of torque as τ = f × r

I × α = f × r

Here, I is the moment of inertia of the sphere

2/5 m r² × α = f × r

α = 5 f /( 2 m r) = (5* 0.02) / (2 * 230 * 10⁻³ * 1.35 * 10⁻²)

α = 16.10 rad / s²

Thus, the angular acceleration is 16.10 rad / s².

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