A machine part has the shape of a solid uniform sphere of mass 230 g and diameter 2.7 cm. The angular acceleration is 16.10 rad / s².
Given that, mass of the sphere is 230 g
diameter is 2.7 cm
Frictional force = 0.02N
Now, we need to calculate angular acceleration. We know the formula of torque as τ = f × r
I × α = f × r
Here, I is the moment of inertia of the sphere
2/5 m r² × α = f × r
α = 5 f /( 2 m r) = (5* 0.02) / (2 * 230 * 10⁻³ * 1.35 * 10⁻²)
α = 16.10 rad / s²
Thus, the angular acceleration is 16.10 rad / s².
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