how large a sample is needed if we wish to be 96% confident that our sample proportion in the question (7) will be within 0.02 of the true fraction of the voting population.

Respuesta :

The sample size for estimating the proportion is 2637.

Given,

How many people should be included in the sample if we want to have 96% confidence that our sample proportion will be within 0.02 of the true fraction of the voting population given the data?

E = 0.02

c = 96% = 0.96

[tex]\hat p[/tex] or P = 0.5 (We have no idea about P, in this case, take P = 0.5)

[tex]\hat p[/tex]  = 1 - [tex]\hat p[/tex]  = 0.5

Now,

α = 1 - c = 1 - 0.96 = 0.04

α/2 = 0.04/2 = 0.02

⇒ α/2 = 2.054 (using z table)

The sample size for estimating the proportion is given by,

[tex]n = Z^2_\alpha _/_2P(1-P)/E^2[/tex]

   = (2.054/0.02)2 * 0.5 * 0.5

   = 2636.8

   = 2637

Hence, the size of sample is 2637.

To learn more about sample size click here:

brainly.com/question/25894237

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