If the same amount of energy was applied to an equal mass of water at 20 °C, its final temperature is 100 °C
q = m C ΔT
ΔT = T - To
q = Heat quantity
m = Mass
C = Specific heat capacity
ΔT = Change in temperature
T = Final temperature
To = Initial temperature
q = 1680 KJ
m = 5 kg
C = 4200 J / kg °C
To = 20 °C
q = m C ( T - To )
1680000 = 5 * 4200 ( T - 20 )
T - 20 = 80
T = 100 °C
Therefore, the final temperature would be 100 °C
The given question is incomplete. The complete question is:
1680 KJ is applied to 5 kg of water. If the same amount of energy was applied to an equal mass of water at 20 °C, what would its final temperature be? The specific heat capacity of water is 4200 J/kg °C.
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