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A 55.0-kg skydiver free falls for a period of time before opening his parachute. what is his kinetic energy when he reaches a velocity of 16.0 meters/second

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The kinetic energy of a moving object is calculated through the equation,
                                 KE = 0.5mv²
where KE is kinetic energy, m is mass, and v is the velocity. Substituting the known values in the problem above,
                                KE = 0.5(55 kg)(16 m/s)²
                                KE = 7,040 J
Thus, the kinetic energy of the skydiver is approximately equal to 7 kJ. 
josebravo585

Answer:

7o4o j

Explanation: