The equation of the line is 2x+y=10 when it that passing through the point and perpendicular to the line.
Given that,
The point is (6,-2) and the line is y=-2x+8
We have to find the equation of the line that passing through the point and perpendicular to the line.
We know that,
The equation of the line is y=mx+c
Here, y and x are the value from the point that is (6,-2)
m is the slope of the line that is -2
c we have to find
-2=-2(6)+c
-2=-12+c
c=-2+12
c=10
The equation of the line is y=-2x+10
2x+y=10
Therefore, The equation of the line is 2x+y=10 when it that passing through the point and perpendicular to the line.
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