The rate of change of the volume of sphere when is decreasing at a constant rate is found as 3319.16 cm³/min.
For the stated question-
Thus, the volume of sphere is found by the equation.
Volume of sphere V = 4/3 πr³
V = 1611 cm³.
1611 = 4/3 πr³
On solving,
r = 7.27 cm
Rate change of the volume;
dV/dt = 4/3 πr² × 3
dV/dt = 4 πr²
Put r = 7.27 cm and π = 3.14
dV/dt = 4 x 3.14 x 7.27²
dV/dt = 3319.16 cm³/min.
Thus, the rate of change of the volume of sphere when is decreasing at a constant rate is found as 3319.16 cm³/min.
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