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what is the exact area of triangle ABC? show all work
The triangle has a 30-degree angle at C, 24m at CB, and a 90-degree angle at B

Respuesta :

Answer:

96√3

Step-by-step explanation:

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Answer:

96√3 m²

Step-by-step explanation:

Triangle ABC is a 30-60-90 triangle.

This is a special right triangle where the measures of its sides are in proportion [tex]x:x\sqrt{3}:2x[/tex]:

  • x is the side opposite the 30° angle
  • x√3 is the side opposite the 60° angle.
  • 2x is the side opposite the right angle.

The side opposite the 30° angle is the height of the triangle.

The side opposite the 60° angle is the base of the triangle and is 24 m.

Therefore, find x:

[tex]\implies x\sqrt{3}=24\\\\ \implies x=\dfrac{24}{\sqrt{3}}\\\\ \implies x=8\sqrt{3}[/tex]

Therefore:

  • Base of the triangle = 24 m
  • Height of the triangle = 8√3 m

[tex]\boxed{\begin{minipage}{4 cm}\underline{Area of a triangle} \\\\$A=\dfrac{1}{2}bh$\\\\where:\\ \phantom{ww}$\bullet$ $b$ is the base. \\ \phantom{ww}$\bullet$ $h$ is the height. \\\end{minipage}}[/tex]

Substitute the found base and height into the formula and solve for area:

[tex]\implies A=\dfrac{1}{2} \cdot 24 \cdot 8\sqrt{3}[/tex]

[tex]\implies A=12 \cdot 8\sqrt{3}[/tex]

[tex]\implies A=96\sqrt{3}\;\; \sf m^2[/tex]

Therefore, the exact area of the triangle is 96√3 m².

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