a car moving at 12.0 m/s crashes into a tree and stops in 0.31 s. calculate the force the seat belt exerts on a passenger in the car to bring him to a halt. the mass of the passenger is 70 kg.

Respuesta :

Answer:

[tex]\huge\boxed{\sf F=2709.7\ N}[/tex]

Explanation:

Given Data:

Velocity = v = 12.0 m/s

Mass = m = 70 kg

Time = 0.31 s

Required:

Force = F = ?

Formula:

[tex]\displaystyle F=\frac{mv}{t}[/tex]

Solution:

Put the given data in the above formula.

[tex]\displaystyle F = \frac{(70)(12)}{0.31} \\\\F=\frac{840}{0.31} \\\\F=2709.7 N\\\\\rule[225]{225}{2}[/tex]