The air track carts in the figure below are sliding to the right at 1.0 m/s. The spring between them has a spring constant of 100 N/m and is compressed 4.1 cm. The cart slides past a flame that burns through the string holding them together.Part A: What is the speed of 100 g cart?Part B: What is the direction of the motion of the 100 g cart? (To the right/ To the left)Part C: What is the speed of 300 g cart?Part D: What is the direction of the motion of the 300 g cart? (To the right/ To the left)

Respuesta :

The air track carts in the figure below are sliding to the right at 1.0 m/s. The spring between them has a spring constant of 100 N/m and is compressed 4.1 cm. So, the speed of the cart will be 3.26m/s

0·3+01 = 0.34 +0-1V, 04 = 0 3V₂+0-1

V₂ = 0·4-0 iv

03so m² + 1 k² = 1 m, v² + + m² = 0·1 +0-3 +1 (130) (0-044)

0.10² + 0·1 (16+u-8v₁) = 3·26

V₁² + 16 +0, -80, -8-26-0=7 V-40, 9-3 =0 2v,2-8v, +16-326-0 5. 51, -1-5)

= taking to left

velocity of mass V₁ = -1.51 m/s 4-1-1-51) 3 V₂ = 1.84 m/s to right.

What reasons a momentum?

A pressure performing for a given quantity of time will extrude an item's momentum. Put every other way, an unbalanced pressure constantly quickens an item - both dashing it up or slowing it down. If the pressure acts contrary the item's motion, it slows the item down.

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