Respuesta :

(2x+14)(2x+20)=832
4x^2+40x+28x+280=832
4x^2+68x+280=832
4x^2+68x+280-832=832-832
4x^2+68x-552=0
(x-6)(4x+92)=0
x=6 or -23
since distance cannot be negative only the positive answer is possible
Solution: The width of the path is 6 meters