Answer: He did 10198.5 J of work.
Explanation:
As it is given in the problem, A 70.0 kg sailor climbs a 28.3 m rope ladder at an angle of 45.0° with the mast.
Calculate the force.
[tex]F=mg[/tex]
Here, m is the mass and g is the acceleration due to gravity.
Put m= 70.0 kg and g=9.8 meter per second.
[tex]F=(70.0)(9.8)[/tex]
[tex]F=(70.0)(9.8)[/tex]
[tex]F=686 N[/tex]
Use the formula for the work done.
[tex]W=Fs\cos \Theta[/tex]
Here, F is the force, s is the displacement and [tex]\Theta[/tex] is the angle between the force and displacement.
Put F=686 N, s=28.3 m and [tex]\Theta[/tex]=45.0°.
[tex]W=(686)(28.3)\cos \(45.0°)[/tex]
[tex]W=(686)(28.3)\cos \(45.0°)[/tex]
[tex]W=10198.5 J[/tex]
Therefore, he did 10198.5 J of work.
