Answer:
The factors of equation [tex]18x^2-21x-15[/tex] is [tex]=3((3x-5)(2x+1))[/tex]
Step-by-step explanation:
Given : Equation [tex]18x^2-21x-15[/tex]
We have to factorize the given equation [tex]18x^2-21x-15[/tex]
Consider the given equation[tex]18x^2-21x-15[/tex]
Taking 3 common from each term, we have,
[tex]=3\left(6x^2-7x-5\right)[/tex]
We will solve the given equation using middle term split method,
-7x can be written as 3x -10x
Equation becomes,
[tex]=3(6x^2+3x-10x-5)[/tex]
Taking 3x common from first two term and -5 common from last two terms, we have,
[tex]=3(3x(2x+1)-5(2x+1))[/tex]
Taking (2x+1) common, we have,
[tex]=3((3x-5)(2x+1))[/tex]
Thus, The factors of equation [tex]18x^2-21x-15[/tex] is [tex]=3((3x-5)(2x+1))[/tex]
