Respuesta :
Here, f(x) = x² - 10x - 4
f(x) + 4 = x² - 10x
Now, half of coefficient of x, -10x/2 = -5x
-5² = 25
We can also solve it further (in case you need):
Then,f(x) + 4 + 25 = (x² - 10x + 25)
f(x) + 29 = (x - 5)²
f(x) = (x - 5)² - 29
In short, Your Answer would be Option D) 25
Hope this helps!
f(x) + 4 = x² - 10x
Now, half of coefficient of x, -10x/2 = -5x
-5² = 25
We can also solve it further (in case you need):
Then,f(x) + 4 + 25 = (x² - 10x + 25)
f(x) + 29 = (x - 5)²
f(x) = (x - 5)² - 29
In short, Your Answer would be Option D) 25
Hope this helps!
25 must be added to the function in order to begin writing the function in vertex form.
The given function is: [tex]f(x) = x^2 - 10x - 4[/tex].
Compare this with [tex]f(x)=ax^2+bx+c[/tex].
So, a = 1, b = -10, c = -4.
In order to get the vertex form, we must add and subtract [tex]\left(\frac{b}{2}\right)^{2}=\left(\frac{-10}{2}\right)^{2}=\left(-5\right)^{2}=25[/tex].
It means 25 must be added to the function in order to begin writing the function in vertex form.
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