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For example:

A 12 oz Coca Cola contains 39g of sugar or C6H12O6. 

To calculate for the molarity of sugar in the soda, convert 39 grams of sugar to moles sugar:

39g/ 180.16 g/mol = 0.216 mol sugar

then, convert 12 oz to L:

12oz / (1oz/0.02957L) = 0.35484 L

therefore the concentration of sugar in the soda is:

M = mol sugar / L sol'n
    = 0.216 mol sugar / 0.35484 L
    = 0.609 M

The molarity of the sugar in the soda bottle of 12 oz is equal to the 0.609M.

How do we calculate molarity?

Molarity of any solution will be calculated as:

M = n/V, where

n = moles of solute

V = volume of solution

Moles will be calcuted as n = W/M, where

W = given mass

M = molar mass

As we know that in 12 oz of coco cola bottle contains 32g of sugar in it so the moles of sugar in 12 oz will be:

n = 32g / 180.16 g/mol = 0.216 mol

V = 12oz = 0.35484 L

The molarity will be calculated as:

M = 0.216 / 0.35484 = 0.609 M

Hence molarity of sugar is 0.609M.

To know more about molarity, visit the below link:
https://brainly.com/question/10608366

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