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B2O3(s) + 3C(s) + 3Cl2 (g) ---> 2 BCl3(g) + 3CO(g)

What is the mass of carbon required in order to produce 6.00 mol BCl3?
A. 234 g
B. 216 g
C. 108 g
D. 0.375 g

Respuesta :

take 6 * 3/2 = 9 mol C needed (the 3/2 is the ratio of C to BCl3)
9 mol * 12 g/mol = 108 g C (12 is the molar mass of C)

Answer C

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