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A rock with a mass of 2.0 kg falls from a cliff. At a height of 5.0 meters, its velocity is 6.0 m/s. What is the mechanical energy of the rock?

Respuesta :

The mechanical energy of the rock is 134.0665 J.

Answer : The mechanical energy of the rock is, 134 J

Solution :

As we know that the mechanical energy is equal to the sum of the kinetic energy and the potential energy.

The formula used for mechanical energy is,

[tex]M.E=K.E+P.E\\\\M.E=(\frac{1}{2}mv^2)+(mgh)[/tex]

where,

M.E = mechanical energy

K.E = kinetic energy

P.E = potential energy

m = mass of an object = 2 Kg

v = velocity of an object = 6 m/s

h = height = 5 m

g = acceleration due to gravity = [tex]9.8m/s^2[/tex]

Now put all the given values in the above formula, we get the mechanical energy of the rock.

[tex]M.E=[\frac{1}{2}(2Kg)\times (6m/s)^2]+(2Kg\times 9.8m/s^2\times 5m)=134\text{ Kg }m^2s^{-2}=134J[/tex]

Therefore, the mechanical energy of the rock is, 134 J