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lukyo
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Solve the trigonometric equation for the variable  x:

                  2
cos(x)  =  ——
                  5


Take the inverse cosine function of both sides, then you get

[tex]\mathsf{x=\pm\,arccos\!\left(\dfrac{2}{5}\right)+k\cdot 360\°}[/tex]

[tex]\mathsf{x=-\,arccos\!\left(\dfrac{2}{5}\right)+k\cdot 360\°~~~or~~~x=arccos\!\left(\dfrac{2}{5}\right)+k\cdot 360\°}[/tex]          ✔

(exact form)


x ≈ 66.42° + k · 360°    or    x ≈ – 66.42° + k · 360°          ✔

(approximate form)


where  k  is an integer.


I hope this helps. =)


Tags:  trigonometric trig equation cosine cos arccos solve trigonometry