acsebar
acsebar acsebar
  • 24-02-2017
  • Chemistry
contestada

How many moles of KCl are required to prepare 1.50 L of 5.4 M KCl?

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NathalyN
NathalyN NathalyN
  • 24-02-2017
5.4 M = moles of solute / 1.50 L 

Multiply both sides by 1.50 L to isolate moles of solute on the right. 

8.1 mol = moles of solute 


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jadyndarnick0 jadyndarnick0
  • 29-11-2018

8.1 mol KCI

This would be the answer.

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